简化计算 (2+1)(2^2+1)(2^4+1)(2^8+1)(2^32+1)+1

题目中是不是少了(2^16+1) ？？？？

(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
＝（2－1）（2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
＝（2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^8-1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^16-1)(2^16+1)(2^32+1)+1
=(2^32-1)(2^32+1)+1
=2^64-1+1
=2^64

补充：没有（2^16+1)项这个题目很难化简下去，答案就不是2^64

=(2-1)(2+1)......(2^32+1)+1
=(2^2-1)(2^2+1).....(2^32+1)+1
=(2^32-1)(2^32+1)+1
=2^64-1+1
=2^64

(2+1)*(2^2+1)*(2^4+1)*(2^8+1)(2^32+1)+1
=(2^2-1)*(2^2+1)*(2^4+1)*(2^8+1)(2^32+1)+1
=(2^4-1)*(2^4+1)*(2^8+1)(2^32+1)+1
=(2^8-1)*(2^8+1)(2^32+1)+1
=2^64
= 1.844674407371 * 10^19